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#191204 - 01/09/08 01:56 AM
Re: No, Audiobytes are HERE!
[Re: EFalardeau]
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devotee
Registered: 10/28/07
Posts: 395
Loc: Cold Lake, AB
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Yeah, my laptop also has the dual SPDIF/headphone jack. If your just using a miniplug RCA cable you're using the headphone functionality. You'd need a digital cable with a mini-plug end or adapter to get the full digital stream.
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M80s/M60/QS8s/EP350; M22s; M3s.
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#191228 - 01/09/08 10:50 AM
Re: No, Audiobytes are HERE!
[Re: Mojo]
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connoisseur
Registered: 08/27/07
Posts: 3250
Loc: Laval, Quebec, Canada
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It might not be your imagination. Some players re-sample systematically to 48K for SPDIF output while playing native 44.1 on their analog circuits (Soundbridge M1001 is a good example of such a difference).
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E = MC2 = ((2M80 + VP180 + 4QS8)/(EP800 + EP500))^(ADA1500 x D2v) Audiobytes! 2M22! 2VP150!
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#191249 - 01/09/08 11:49 AM
Re: No, Audiobytes are HERE!
[Re: EFalardeau]
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shareholder in the making
Registered: 05/03/03
Posts: 17420
Loc: NoVA
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But he's not using SPDIF if he's plugging the Audiobytes into that dual jack; he's using, essentially, a headphone jack.
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#191251 - 01/09/08 11:56 AM
Re: No, Audiobytes are HERE!
[Re: Ken.C]
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connoisseur
Registered: 08/27/07
Posts: 3250
Loc: Laval, Quebec, Canada
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It does not mean it is the same output than the single-usage headphone jack.
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E = MC2 = ((2M80 + VP180 + 4QS8)/(EP800 + EP500))^(ADA1500 x D2v) Audiobytes! 2M22! 2VP150!
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#191255 - 01/09/08 12:11 PM
Re: No, Audiobytes are HERE!
[Re: EFalardeau]
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shareholder in the making
Registered: 05/03/03
Posts: 17420
Loc: NoVA
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Why not? Why would a manufacturer put a separate audio processor in for outputs that are essentially doing the same thing? Sure, the traces are going to be a little different, but do you think that there's going to be that much variation in the sound (audibly) from a few millimeters of copper?
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DON'T... call me stupid!
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#191257 - 01/09/08 12:17 PM
Re: No, Audiobytes are HERE!
[Re: Ken.C]
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connoisseur
Registered: 08/27/07
Posts: 3250
Loc: Laval, Quebec, Canada
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It might not be coming out of the same chip.
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E = MC2 = ((2M80 + VP180 + 4QS8)/(EP800 + EP500))^(ADA1500 x D2v) Audiobytes! 2M22! 2VP150!
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#191259 - 01/09/08 12:19 PM
Re: No, Audiobytes are HERE!
[Re: EFalardeau]
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shareholder in the making
Registered: 05/03/03
Posts: 17420
Loc: NoVA
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So they've put 2 sound chips on the board.
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#191261 - 01/09/08 12:23 PM
Re: No, Audiobytes are HERE!
[Re: Ken.C]
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connoisseur
Registered: 08/27/07
Posts: 3250
Loc: Laval, Quebec, Canada
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This is just speculation (on BOTH sides). Two outputs serving two purposes can very well have two separate chips. The Soundbrige mentionned earlier is a perfect exemple of that. Since, again, we are all speculating here, let's try to keep this friendly and avoid putting words into posts! 
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E = MC2 = ((2M80 + VP180 + 4QS8)/(EP800 + EP500))^(ADA1500 x D2v) Audiobytes! 2M22! 2VP150!
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#191263 - 01/09/08 12:27 PM
Re: No, Audiobytes are HERE!
[Re: EFalardeau]
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shareholder in the making
Registered: 05/03/03
Posts: 17420
Loc: NoVA
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Oh fine... as usual, I should be a little more careful with my posting in the morning. Sorry about that.
However, from my knowledge of system architecture in computers, I would wager that the outputs are both from the same chip, unless there is sound processing on the south bridge (rare, possibly nonexistent) or has an "add-on" chip/card on the board (such as an X-Fi) in addition to the typical Realtek chip. '
This post is an invitation for someone to come along and tell me I know jack-all about system architecture.
Edited by kcarlile (01/09/08 12:27 PM)
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