If I read this correctly, if you wire from a channel on your amp to speaker A, then continue on from speaker A's terminal to speaker B's cooresponding terminals, you will have created a Parallel Circuit. The laws of Electricity dictate that this will REDUCE the overall resistance placed on the amp. So technically it could look like a smaller load, which would allow more output. However some amps can not handle too low of a load. (8ohms in parallel with 8 ohms = 4 ohms, and with 4 ohms speakers, 4 and 4 =2)
* This is a theoretical discussion of resistances and loads of speakers. As with all theories, there are complicated calcualtions, and we also are limiting a speaker to being a resistance - when it actually is complex load of inductance, capacitance and resistance. The stance taken is to reduce complexity, and still maintain an accurate explanation.
I have experimented with this:
- wire a SINGLE channel to the speakers general area
- wire the positive to speaker A positive terminal
- wire the negative to speaker B negative terminal
- connect Speaker A negative to Speaker B positive
This does the opposite of the above Parallel Circuit, and creates a series circuit. A series circuit is the addition of both loads ( example 8ohms +8ohms = 16 ohms,and with 4 ohm speakers, 4 + 4=8 )
Again, this has worked, and was recommended by NAD on some of there amps.
Regards,
BBIBH
