Just out of general intuition, it would be safe to assume that the impedence would rise since you are distributing the load on two amplifiers (and thus halving the number of drivers that run in parallel). When you run two identical drivers in parallel, impedence is halved, as you most likely already know.
Now, I'd be sure that the woofers still are closer to four to six ohms, and that the tweeters and mids would be at eight or higher. I would also think it is safe to assume that the drivers are wired in parallel internally because since it's not a dipole speaker.
