I'm not sure what the confusion is over. 2 amps in series = 2 times applied voltage. V proportional to 'I' implies 2x the current. Power proportional to 'I' squared implies 4 times the power.

The load never changes, the currents are doubled through the system.

If you just had one amp with double the normal current it would be as if the normal resistance was lowered by a factor of 2.

edit* Ha, that was pretty poorly stated!

Last edited by Babalu; 08/12/05 04:31 PM.