Normally, we don't give this info out until you've been officially indoctrinated into the society, but you seem like a nice guy.....

Ok, think of a beer case, eh. Now as you know, the beers are arranged 4 abreast and 6 long. 6 times 4 is 24 - no problem. In fact, its a beauty. But 6 divided by 4 is 1.5. Any beer drinker knows that it is physically impossible to drink 1.5 beer. No bout a doubt it, you are going to drink the full 2 beer, eh. That leaves you with 22 beer. (Unless your buddy Blair is over, then there would be 20) Now, 20 divided by 6 is 3.3. Do you see the patern taking shape here? There is no easy solution but to drink the whole box, bye. And that's were the problem lies, eh.

So there you go. Now you understand why the room dimensions are so important.

Actually, it has to do with the wavelengths of certain frequencies.

Quote:

If the wavelength of a particular note happens to be the same, or an even fraction (1/2, 1/3, ¼, etc.) as one of the room’s dimensions, there’ll be a standing wave created. Standing waves cause certain frequencies to be accentuated at various locations in the room and reduced in others. Basically it can cause one seat in the room have great sound and another to have very poor sound.

In order to reduce the effects of standing waves, it is best to have the room follow certain dimensional ratios. (ratios of HxWxL). First of all, run & hide from a room that is a perfect cube. You should avoid rooms with any ratios that are perfect multiples of each other. An example of a poor room would be a 15’ x 20’ room with a 10’ ceiling. Some good ratios are 1 x 1.3 x 1.7 or 1 x 1.3 x 1.9 or .9 x 1.3 x 1.6. It is easier to work with a rectangular room because the good speaker and seating locations are easier to predict.







Shawn

Epic 80/600 + M3's + M3 Algonquins + M2 Computer + EP125
I think I'm developing an addiction.